2017-03-25 20:03 GMT+01:00 James Sherman Jr. <

> On Sat, Mar 25, 2017 at 2:51 PM, Juan Pablo Carbajal

> <

[hidden email]> wrote:

>> On Sat, Mar 25, 2017 at 6:48 PM, José Luis García Pallero

>> <

[hidden email]> wrote:

>>> Hello:

>>>

>>> Using this variables:

>>>

>>> a = 2;

>>> b = [1 2 3];

>>>

>>> For the operation a/b or 2/b or b/2 I obtain an error in Octave and

>>> Matlab due to wrong dimensions. But if I declare b as a vector column

>>> as b=[1 2 3]' I obtain in Octave:

>>>

>>>>> a/b

>>> ans =

>>>

>>> 0.14286 0.28571 0.42857

>>>

>>> and in Matlab:

>>>

>>>>> a/b

>>>

>>> ans =

>>>

>>> 0 0 0.6667

>>>

>>> What is the reason of this difference? Why the operation is legal with

>>> b as column vector and illegal with row vector?

>>>

>>> Thanks

>>>

>>> --

>>> *****************************************

>>> José Luis García Pallero

>>>

[hidden email]
>>> (o<

>>> / / \

>>> V_/_

>>> Use Debian GNU/Linux and enjoy!

>>> *****************************************

>>>

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>>>

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>>>

https://lists.gnu.org/mailman/listinfo/help-octave>> In Octave a/b when b is a matrix (any size), is equivalent to

>> a*inv(b), in this case a*pinv(b) (try it out).

>> I can't see what matlab is doing, but the last element is 2/3.

>>

>> I also do not understand why there is an error in the first case,

>> should given the same result...i.e. apply a*pinv(b) when b is a row

>> vector

>>

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https://lists.gnu.org/mailman/listinfo/help-octave>

> I just tried this on MATLAB version 2016a, and got the following results:

>

>>> a = 2;

>>> b = [1 2 3];

>>> 2/b

> Error using /

> Matrix dimensions must agree.

>>> a/b

> Error using /

> Matrix dimensions must agree.

>>> b/2

> ans =

> 0.5000 1.0000 1.5000

>

> Are you sure that b/2 caused an error? That is well defined and

> should produce elementwise division by 2.

Sorry, it was a mistake. b/2 peoduces correct results