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using cellfunction

BOKU
Hello,

I would to apply a function to a 3x371 cell array

so my question would if there is a solution to the following

for i=1:numel(values)                              ####### wrapping
elements to get access in cellfunktion
####### because cellfunction does just deliver the cellaray
    wrapobj{1,i}=foundimfilt{i};               #######  I hoped that it
will deliver the 3x1 cell
    wrapobj{2,i}=ref{i};
    wrapobj{3,i}=meanval{i};

endfor


function [pointsel]= similarpoints(f)

      idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3&
f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ...    #######
so that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 |
f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function

idxl=imcomplement(idxl);
pointsel=medfilt2(idxl,[10,10]);
endfunction


pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false
); ############ but unfortunately it seems that i don't                
                    get the full  cell


error: f(7): out of bound 1
error: called from
     similarpoints at line 3 column 10


is there a solution for the indexing or the delivering the needed
informations for the function. Basicly i want to apply an individual
filter to every cell and I need the information stored in wrapobj{3,i}
to apply it on the matrix stored in wrapobj{1,i}!

wrapobj is a 3x371 cell array.

i would appreciate any help on this

cheers chris




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Re: using cellfunction

Juan Pablo Carbajal-2
On Thu, May 11, 2017 at 9:41 PM, BOKU
<[hidden email]> wrote:

> Hello,
>
> I would to apply a function to a 3x371 cell array
>
> so my question would if there is a solution to the following
>
> for i=1:numel(values)                              ####### wrapping elements
> to get access in cellfunktion
> ####### because cellfunction does just deliver the cellaray
>    wrapobj{1,i}=foundimfilt{i};               #######  I hoped that it will
> deliver the 3x1 cell
>    wrapobj{2,i}=ref{i};
>    wrapobj{3,i}=meanval{i};
>
> endfor
>
>
> function [pointsel]= similarpoints(f)
>
>      idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3&
> f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ...    ####### so
> that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 |
> f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function
>
> idxl=imcomplement(idxl);
> pointsel=medfilt2(idxl,[10,10]);
> endfunction
>
>
> pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false );
> ############ but unfortunately it seems that i don't
> get the full  cell
>
>
> error: f(7): out of bound 1
> error: called from
>     similarpoints at line 3 column 10
>
>
> is there a solution for the indexing or the delivering the needed
> informations for the function. Basicly i want to apply an individual filter
> to every cell and I need the information stored in wrapobj{3,i} to apply it
> on the matrix stored in wrapobj{1,i}!
>
> wrapobj is a 3x371 cell array.
>
> i would appreciate any help on this
>
> cheers chris
>
>
>
>
> _______________________________________________
> Help-octave mailing list
> [hidden email]
> https://lists.gnu.org/mailman/listinfo/help-octave

Hi,
cellfun respects the size of the input, that is

> c = {1,4,7,10;2,5,8,11;3,6,9,12};
> f=@(x) x-1;
> cp = cellfun (f,c)
cp =

    0    3    6    9
    1    4    7   10
    2    5    8   11

If you input is a 3x371 cell, then the output of cellfun will be a
cell of the same size. If the output of the function you evaluate on
each cell element is an array or cell, then you should tell cellfun
that 'UniformOutput' is false, e.g.

> f=@(x) linspace(1,x,3);
> cp = cellfun (f,c,'UniformOutput', false);
> whos cp
Variables in the current scope:

   Attr Name        Size                     Bytes  Class
   ==== ====        ====                     =====  =====
        cp          3x4                        288  cell

Total is 12 elements using 288 bytes

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Re: using cellfunction

BOKU

Thank you for your response ,

yes I do understand,

but I did already "UniformOutput", false

The problem is the function, as I want to apply a function which needs more than just the matrix from the cell x{1,1} (for the first cell), no I need furthermore the data which are stored in   x{3,1}  (for the first cell). And It seems that I cannot index the matrix. I just dont know what cellfunction does with the cell.. I mean if I do @mean or @(x) x-1 i could basicly do mean(cell2mat(x)) and it's done! But if i have a {1,3} cell array in which {1,1} is a matrix of let's say 300X300X300 and {1,2} is a 1X12 array, and {1,3} is a an 200,120 array what happens then. but that is exactly what i want to do I want to applay a function to  {1:end,1} with individual datas stored in {1:end,3}. And idon't want to loop because it's incredible slow. It takes about 20 min looping over this cell and I have several hundreds of them. So I want to find another solution.  

x{1,i}=foundimfilt{i};

x{2,i}=ref{i};

x{3,i}=meanval{i};


function [y]= doit(x)

idxl=x(1,1)(:,:,1)>x(3,1)(7)+0.3 | x(1,1)(:,:,1)<x(3,7)-0.3

x(1,1)(:,:,2)>x(1,3)(6)+0.3 | x(1,1)(:,:,2)<x(1,3)(6)-0.3 ...

&x(1,1)(:,:,3)>x(1,3)(8)+0.3 | x(1,1)(:,:,3)<x(1,3)(8)-0.3;

idxl=imcomplement(idxl);

pointsel=medfilt2(idxl,[10,10]);

endfunction


pointselection = cellfun(@doit, x ,"UniformOutput" ,false );


On 2017-05-11 22:11, Juan Pablo Carbajal wrote:
On Thu, May 11, 2017 at 9:41 PM, BOKU
[hidden email] wrote:
Hello,

I would to apply a function to a 3x371 cell array

so my question would if there is a solution to the following

for i=1:numel(values)                              ####### wrapping elements
to get access in cellfunktion
####### because cellfunction does just deliver the cellaray
   wrapobj{1,i}=foundimfilt{i};               #######  I hoped that it will
deliver the 3x1 cell
   wrapobj{2,i}=ref{i};
   wrapobj{3,i}=meanval{i};

endfor


function [pointsel]= similarpoints(f)

     idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3&
f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ...    ####### so
that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 |
f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function

idxl=imcomplement(idxl);
pointsel=medfilt2(idxl,[10,10]);
endfunction


pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false );
############ but unfortunately it seems that i don't
get the full  cell


error: f(7): out of bound 1
error: called from
    similarpoints at line 3 column 10


is there a solution for the indexing or the delivering the needed
informations for the function. Basicly i want to apply an individual filter
to every cell and I need the information stored in wrapobj{3,i} to apply it
on the matrix stored in wrapobj{1,i}!

wrapobj is a 3x371 cell array.

i would appreciate any help on this

cheers chris




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Hi,
cellfun respects the size of the input, that is

c = {1,4,7,10;2,5,8,11;3,6,9,12};
f=@(x) x-1;
cp = cellfun (f,c)
cp =

    0    3    6    9
    1    4    7   10
    2    5    8   11

If you input is a 3x371 cell, then the output of cellfun will be a
cell of the same size. If the output of the function you evaluate on
each cell element is an array or cell, then you should tell cellfun
that 'UniformOutput' is false, e.g.

f=@(x) linspace(1,x,3);
cp = cellfun (f,c,'UniformOutput', false);
whos cp
Variables in the current scope:

   Attr Name        Size                     Bytes  Class
   ==== ====        ====                     =====  =====
        cp          3x4                        288  cell

Total is 12 elements using 288 bytes


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Re: using cellfunction

Juan Pablo Carbajal-2
On Thu, May 11, 2017 at 10:42 PM, BOKU
<[hidden email]> wrote:

> Thank you for your response ,
>
> yes I do understand,
>
> but I did already "UniformOutput", false
>
> The problem is the function, as I want to apply a function which needs more
> than just the matrix from the cell x{1,1} (for the first cell), no I need
> furthermore the data which are stored in   x{3,1}  (for the first cell). And
> It seems that I cannot index the matrix. I just dont know what cellfunction
> does with the cell.. I mean if I do @mean or @(x) x-1 i could basicly do
> mean(cell2mat(x)) and it's done! But if i have a {1,3} cell array in which
> {1,1} is a matrix of let's say 300X300X300 and {1,2} is a 1X12 array, and
> {1,3} is a an 200,120 array what happens then. but that is exactly what i
> want to do I want to applay a function to  {1:end,1} with individual datas
> stored in {1:end,3}. And idon't want to loop because it's incredible slow.
> It takes about 20 min looping over this cell and I have several hundreds of
> them. So I want to find another solution.
>
> x{1,i}=foundimfilt{i};
>
> x{2,i}=ref{i};
>
> x{3,i}=meanval{i};
>
>
> function [y]= doit(x)
>
> idxl=x(1,1)(:,:,1)>x(3,1)(7)+0.3 | x(1,1)(:,:,1)<x(3,7)-0.3
>
> x(1,1)(:,:,2)>x(1,3)(6)+0.3 | x(1,1)(:,:,2)<x(1,3)(6)-0.3 ...
>
> &x(1,1)(:,:,3)>x(1,3)(8)+0.3 | x(1,1)(:,:,3)<x(1,3)(8)-0.3;
>
> idxl=imcomplement(idxl);
>
> pointsel=medfilt2(idxl,[10,10]);
>
> endfunction
>
>
> pointselection = cellfun(@doit, x ,"UniformOutput" ,false );
>
>
> On 2017-05-11 22:11, Juan Pablo Carbajal wrote:
>
> On Thu, May 11, 2017 at 9:41 PM, BOKU
> <[hidden email]> wrote:
>
> Hello,
>
> I would to apply a function to a 3x371 cell array
>
> so my question would if there is a solution to the following
>
> for i=1:numel(values)                              ####### wrapping elements
> to get access in cellfunktion
> ####### because cellfunction does just deliver the cellaray
>    wrapobj{1,i}=foundimfilt{i};               #######  I hoped that it will
> deliver the 3x1 cell
>    wrapobj{2,i}=ref{i};
>    wrapobj{3,i}=meanval{i};
>
> endfor
>
>
> function [pointsel]= similarpoints(f)
>
>      idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3&
> f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ...    ####### so
> that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 |
> f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function
>
> idxl=imcomplement(idxl);
> pointsel=medfilt2(idxl,[10,10]);
> endfunction
>
>
> pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false );
> ############ but unfortunately it seems that i don't
> get the full  cell
>
>
> error: f(7): out of bound 1
> error: called from
>     similarpoints at line 3 column 10
>
>
> is there a solution for the indexing or the delivering the needed
> informations for the function. Basicly i want to apply an individual filter
> to every cell and I need the information stored in wrapobj{3,i} to apply it
> on the matrix stored in wrapobj{1,i}!
>
> wrapobj is a 3x371 cell array.
>
> i would appreciate any help on this
>
> cheers chris
>
>
>
>
> _______________________________________________
> Help-octave mailing list
> [hidden email]
> https://lists.gnu.org/mailman/listinfo/help-octave
>
> Hi,
> cellfun respects the size of the input, that is
>
> c = {1,4,7,10;2,5,8,11;3,6,9,12};
> f=@(x) x-1;
> cp = cellfun (f,c)
>
> cp =
>
>     0    3    6    9
>     1    4    7   10
>     2    5    8   11
>
> If you input is a 3x371 cell, then the output of cellfun will be a
> cell of the same size. If the output of the function you evaluate on
> each cell element is an array or cell, then you should tell cellfun
> that 'UniformOutput' is false, e.g.
>
> f=@(x) linspace(1,x,3);
> cp = cellfun (f,c,'UniformOutput', false);
> whos cp
>
> Variables in the current scope:
>
>    Attr Name        Size                     Bytes  Class
>    ==== ====        ====                     =====  =====
>         cp          3x4                        288  cell
>
> Total is 12 elements using 288 bytes
>
>

cellfun, arrayfun and similar functions apply the function to each
element of the cell. so if the function can process all the elements
in the cell, e.g. different sized matrices, scalars, strings, etc..
then cellfun will just apply it to each element. It is the
generalization of the "element-wise" behavior of functions applied to
arrays, i.e. sin, tanh, exp, abs, etc...

But cellfun can also work in two cells, advancing on each other
simultaneously and implement element-wise functions of many inputs
(n-arity), for you case you could do

cellfun (your_func, your_cell(1,:), your_cell(3,:), 'unif', 0)

Does it work?

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Re: using cellfunction

Juan Pablo Carbajal-2
On Thu, May 11, 2017 at 11:47 PM, Juan Pablo Carbajal
<[hidden email]> wrote:

> On Thu, May 11, 2017 at 10:42 PM, BOKU
> <[hidden email]> wrote:
>> Thank you for your response ,
>>
>> yes I do understand,
>>
>> but I did already "UniformOutput", false
>>
>> The problem is the function, as I want to apply a function which needs more
>> than just the matrix from the cell x{1,1} (for the first cell), no I need
>> furthermore the data which are stored in   x{3,1}  (for the first cell). And
>> It seems that I cannot index the matrix. I just dont know what cellfunction
>> does with the cell.. I mean if I do @mean or @(x) x-1 i could basicly do
>> mean(cell2mat(x)) and it's done! But if i have a {1,3} cell array in which
>> {1,1} is a matrix of let's say 300X300X300 and {1,2} is a 1X12 array, and
>> {1,3} is a an 200,120 array what happens then. but that is exactly what i
>> want to do I want to applay a function to  {1:end,1} with individual datas
>> stored in {1:end,3}. And idon't want to loop because it's incredible slow.
>> It takes about 20 min looping over this cell and I have several hundreds of
>> them. So I want to find another solution.
>>
>> x{1,i}=foundimfilt{i};
>>
>> x{2,i}=ref{i};
>>
>> x{3,i}=meanval{i};
>>
>>
>> function [y]= doit(x)
>>
>> idxl=x(1,1)(:,:,1)>x(3,1)(7)+0.3 | x(1,1)(:,:,1)<x(3,7)-0.3
>>
>> x(1,1)(:,:,2)>x(1,3)(6)+0.3 | x(1,1)(:,:,2)<x(1,3)(6)-0.3 ...
>>
>> &x(1,1)(:,:,3)>x(1,3)(8)+0.3 | x(1,1)(:,:,3)<x(1,3)(8)-0.3;
>>
>> idxl=imcomplement(idxl);
>>
>> pointsel=medfilt2(idxl,[10,10]);
>>
>> endfunction
>>
>>
>> pointselection = cellfun(@doit, x ,"UniformOutput" ,false );
>>
>>
>> On 2017-05-11 22:11, Juan Pablo Carbajal wrote:
>>
>> On Thu, May 11, 2017 at 9:41 PM, BOKU
>> <[hidden email]> wrote:
>>
>> Hello,
>>
>> I would to apply a function to a 3x371 cell array
>>
>> so my question would if there is a solution to the following
>>
>> for i=1:numel(values)                              ####### wrapping elements
>> to get access in cellfunktion
>> ####### because cellfunction does just deliver the cellaray
>>    wrapobj{1,i}=foundimfilt{i};               #######  I hoped that it will
>> deliver the 3x1 cell
>>    wrapobj{2,i}=ref{i};
>>    wrapobj{3,i}=meanval{i};
>>
>> endfor
>>
>>
>> function [pointsel]= similarpoints(f)
>>
>>      idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3&
>> f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ...    ####### so
>> that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 |
>> f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function
>>
>> idxl=imcomplement(idxl);
>> pointsel=medfilt2(idxl,[10,10]);
>> endfunction
>>
>>
>> pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false );
>> ############ but unfortunately it seems that i don't
>> get the full  cell
>>
>>
>> error: f(7): out of bound 1
>> error: called from
>>     similarpoints at line 3 column 10
>>
>>
>> is there a solution for the indexing or the delivering the needed
>> informations for the function. Basicly i want to apply an individual filter
>> to every cell and I need the information stored in wrapobj{3,i} to apply it
>> on the matrix stored in wrapobj{1,i}!
>>
>> wrapobj is a 3x371 cell array.
>>
>> i would appreciate any help on this
>>
>> cheers chris
>>
>>
>>
>>
>> _______________________________________________
>> Help-octave mailing list
>> [hidden email]
>> https://lists.gnu.org/mailman/listinfo/help-octave
>>
>> Hi,
>> cellfun respects the size of the input, that is
>>
>> c = {1,4,7,10;2,5,8,11;3,6,9,12};
>> f=@(x) x-1;
>> cp = cellfun (f,c)
>>
>> cp =
>>
>>     0    3    6    9
>>     1    4    7   10
>>     2    5    8   11
>>
>> If you input is a 3x371 cell, then the output of cellfun will be a
>> cell of the same size. If the output of the function you evaluate on
>> each cell element is an array or cell, then you should tell cellfun
>> that 'UniformOutput' is false, e.g.
>>
>> f=@(x) linspace(1,x,3);
>> cp = cellfun (f,c,'UniformOutput', false);
>> whos cp
>>
>> Variables in the current scope:
>>
>>    Attr Name        Size                     Bytes  Class
>>    ==== ====        ====                     =====  =====
>>         cp          3x4                        288  cell
>>
>> Total is 12 elements using 288 bytes
>>
>>
>
> cellfun, arrayfun and similar functions apply the function to each
> element of the cell. so if the function can process all the elements
> in the cell, e.g. different sized matrices, scalars, strings, etc..
> then cellfun will just apply it to each element. It is the
> generalization of the "element-wise" behavior of functions applied to
> arrays, i.e. sin, tanh, exp, abs, etc...
>
> But cellfun can also work in two cells, advancing on each other
> simultaneously and implement element-wise functions of many inputs
> (n-arity), for you case you could do
>
> cellfun (your_func, your_cell(1,:), your_cell(3,:), 'unif', 0)
>
> Does it work?

you can also do arrayfun on the index...

index = 1:size(your_cell,2);
arrayfun (@(i)your_func(your_cell{1,i},your_cell{3,i}), index, 'unif', 0)

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Re: using cellfunction

BOKU
Hey sorry for the late answer,

okay now i got it, yes it works like you mentioned! Thank you very much.
You really helped me out!

for me the following worked.

do a lot of repmat and cell2mat and mat2cell so that you get all the
variables to the same size eg 1X371 of cell arrays and then apply the
function as cellfunction. all the ingoing variables to cellfunction
needs to have the same size.

size(var1) =  1X371X3

size(var2) =  1X371

size(var3) =  1X371

function[outp]=myfun(var1,var2,var3);

l=dosometing(var1);

domore=l*.var2;

doevenmore=domore-var3;

outp=[doevenmore./domore];

endfunction;

outcellfun=cellfun(@myfunc, var1,var2,var3,'unif',0);

cheers chris


On 2017-05-11 23:49, Juan Pablo Carbajal wrote:

> On Thu, May 11, 2017 at 11:47 PM, Juan Pablo Carbajal
> <[hidden email]> wrote:
>> On Thu, May 11, 2017 at 10:42 PM, BOKU
>> <[hidden email]> wrote:
>>> Thank you for your response ,
>>>
>>> yes I do understand,
>>>
>>> but I did already "UniformOutput", false
>>>
>>> The problem is the function, as I want to apply a function which needs more
>>> than just the matrix from the cell x{1,1} (for the first cell), no I need
>>> furthermore the data which are stored in   x{3,1}  (for the first cell). And
>>> It seems that I cannot index the matrix. I just dont know what cellfunction
>>> does with the cell.. I mean if I do @mean or @(x) x-1 i could basicly do
>>> mean(cell2mat(x)) and it's done! But if i have a {1,3} cell array in which
>>> {1,1} is a matrix of let's say 300X300X300 and {1,2} is a 1X12 array, and
>>> {1,3} is a an 200,120 array what happens then. but that is exactly what i
>>> want to do I want to applay a function to  {1:end,1} with individual datas
>>> stored in {1:end,3}. And idon't want to loop because it's incredible slow.
>>> It takes about 20 min looping over this cell and I have several hundreds of
>>> them. So I want to find another solution.
>>>
>>> x{1,i}=foundimfilt{i};
>>>
>>> x{2,i}=ref{i};
>>>
>>> x{3,i}=meanval{i};
>>>
>>>
>>> function [y]= doit(x)
>>>
>>> idxl=x(1,1)(:,:,1)>x(3,1)(7)+0.3 | x(1,1)(:,:,1)<x(3,7)-0.3
>>>
>>> x(1,1)(:,:,2)>x(1,3)(6)+0.3 | x(1,1)(:,:,2)<x(1,3)(6)-0.3 ...
>>>
>>> &x(1,1)(:,:,3)>x(1,3)(8)+0.3 | x(1,1)(:,:,3)<x(1,3)(8)-0.3;
>>>
>>> idxl=imcomplement(idxl);
>>>
>>> pointsel=medfilt2(idxl,[10,10]);
>>>
>>> endfunction
>>>
>>>
>>> pointselection = cellfun(@doit, x ,"UniformOutput" ,false );
>>>
>>>
>>> On 2017-05-11 22:11, Juan Pablo Carbajal wrote:
>>>
>>> On Thu, May 11, 2017 at 9:41 PM, BOKU
>>> <[hidden email]> wrote:
>>>
>>> Hello,
>>>
>>> I would to apply a function to a 3x371 cell array
>>>
>>> so my question would if there is a solution to the following
>>>
>>> for i=1:numel(values)                              ####### wrapping elements
>>> to get access in cellfunktion
>>> ####### because cellfunction does just deliver the cellaray
>>>     wrapobj{1,i}=foundimfilt{i};               #######  I hoped that it will
>>> deliver the 3x1 cell
>>>     wrapobj{2,i}=ref{i};
>>>     wrapobj{3,i}=meanval{i};
>>>
>>> endfor
>>>
>>>
>>> function [pointsel]= similarpoints(f)
>>>
>>>       idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3&
>>> f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ...    ####### so
>>> that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 |
>>> f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function
>>>
>>> idxl=imcomplement(idxl);
>>> pointsel=medfilt2(idxl,[10,10]);
>>> endfunction
>>>
>>>
>>> pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false );
>>> ############ but unfortunately it seems that i don't
>>> get the full  cell
>>>
>>>
>>> error: f(7): out of bound 1
>>> error: called from
>>>      similarpoints at line 3 column 10
>>>
>>>
>>> is there a solution for the indexing or the delivering the needed
>>> informations for the function. Basicly i want to apply an individual filter
>>> to every cell and I need the information stored in wrapobj{3,i} to apply it
>>> on the matrix stored in wrapobj{1,i}!
>>>
>>> wrapobj is a 3x371 cell array.
>>>
>>> i would appreciate any help on this
>>>
>>> cheers chris
>>>
>>>
>>>
>>>
>>> _______________________________________________
>>> Help-octave mailing list
>>> [hidden email]
>>> https://lists.gnu.org/mailman/listinfo/help-octave
>>>
>>> Hi,
>>> cellfun respects the size of the input, that is
>>>
>>> c = {1,4,7,10;2,5,8,11;3,6,9,12};
>>> f=@(x) x-1;
>>> cp = cellfun (f,c)
>>>
>>> cp =
>>>
>>>      0    3    6    9
>>>      1    4    7   10
>>>      2    5    8   11
>>>
>>> If you input is a 3x371 cell, then the output of cellfun will be a
>>> cell of the same size. If the output of the function you evaluate on
>>> each cell element is an array or cell, then you should tell cellfun
>>> that 'UniformOutput' is false, e.g.
>>>
>>> f=@(x) linspace(1,x,3);
>>> cp = cellfun (f,c,'UniformOutput', false);
>>> whos cp
>>>
>>> Variables in the current scope:
>>>
>>>     Attr Name        Size                     Bytes  Class
>>>     ==== ====        ====                     =====  =====
>>>          cp          3x4                        288  cell
>>>
>>> Total is 12 elements using 288 bytes
>>>
>>>
>> cellfun, arrayfun and similar functions apply the function to each
>> element of the cell. so if the function can process all the elements
>> in the cell, e.g. different sized matrices, scalars, strings, etc..
>> then cellfun will just apply it to each element. It is the
>> generalization of the "element-wise" behavior of functions applied to
>> arrays, i.e. sin, tanh, exp, abs, etc...
>>
>> But cellfun can also work in two cells, advancing on each other
>> simultaneously and implement element-wise functions of many inputs
>> (n-arity), for you case you could do
>>
>> cellfun (your_func, your_cell(1,:), your_cell(3,:), 'unif', 0)
>>
>> Does it work?
> you can also do arrayfun on the index...
>
> index = 1:size(your_cell,2);
> arrayfun (@(i)your_func(your_cell{1,i},your_cell{3,i}), index, 'unif', 0)


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