

This post was updated on .
a = (1,3,4,6,8,9,0,5,4,)
b = (3)
c = (4,56,7,8,5,1)
a, b,c are saved in .vec extension
for t1 =1:1:length(a)
for t2=1:1:length(b)
for t3=1:1:length(c)
period_fun(a,b,c)=time(p);
p=p+1;
end
end
end
So this code will give me the time
period fun(5,1,3) which means it will fetch
5th element of a = 8, 1st element of b = 3, 3rd element of c = 7, and the
output is time = 1.1
Now just by looking the output time 1.1 i want to extract the 5th element of
a or the 1st element of b or 3rd element of c and get that element as
output
is it possible ?

Sent from: https://octave.1599824.n4.nabble.com/OctaveGeneralf1599825.html

Administrator

a = (1,3,4,6,8,9,0,5,4,)
b = (3)
c = (4,56,7,8,5,1)
a, b,c are saved in .vec extension
for t1 =1:1:length(a)
for t2=1:1:length(b)
for t3=1:1:length(c)
period_fun(a,b,c)=time(p);
p=p+1;
end
end
end
So this code will give me the time
period fun(5,1,3) which means it will fetch
5th element of a = 8, 1st element of b = 1, 3rd element of c = 7, and the
output is time = 1.1
Now just by looking the output time 1.1 i want to extract the 5th element of
a or the 1st element of b or 3rd element of c and get that element as
output
is it possible ?
I'm still not clear on what you're actually trying to do.
what is p?
is the time function just the octave builtin function time()? I don't think that can take an input. Or is there some other function/variable you've left out of this description?
and period_fun is just a 3dimensional array of ... the time the iteration occurred?
The pseudocode above obviously wouldn't run in Octave. What have you actually tried to run in octave, and what has/hasn't worked? It's hard for us to help when you're only providing part of the information.
What exact information are you starting with (everything), and what exactly would you like as an output?

