> Ok, let me try and explain it better

> I have two functions, say f(x) and g(x), which give vectors as outputs, so

> something like:

> f=@(x) [x^2 x^3]

> g=@(x) [x 5*x]

> and these must make up a vector function with combinations of f and g, for

> example:

> [x^2 (x^3)+(x) 5(x)]. So in other words the first two values must be from f

> and added to these in the spaces two and 3 must be the values from g.

>

> Is that clearer?

>

>

>

> On 9 August 2012 13:38, Juan Pablo Carbajal <

[hidden email]> wrote:

>>

>> On Thu, Aug 9, 2012 at 8:59 AM, Francesco Potortì <

[hidden email]>

>> wrote:

>> >>I am trying to assemble a function into a matrix or a vector but I have

>> >> not

>> >>found a way to do so except for typing it out manually, which is not

>> >>possible as the it would be around 100 long and wide and changes after

>> >>every timestep. The following represents what I am trying to do:

>> >>

>> >>f=@(x) [x^2 x 1]

>> >>then I want to put a number of these into a vector so that the final

>> >> vector

>> >>would look like:

>> >>vect=@(x) [x^2 x+x^2 1+x 1]

>> >>Here I have added have done something like:

>> >>vect=@(x) [f(x)(1) f(x)(2)+f(x)(1) f(x)(3)+f(x)(2) +f(x)(3)]

>> >>So basically having a vector with f in 1 to 3 added to f in positions 2

>> >> to

>> >>4. Obviously this would have to run in a loop as it is well over 100

>> >> wide.

>> >

>> > As far as I am concerned, you should try to explain it better: I read it

>> > carefully, but could nt make out what you need.

>> >

>> > --

>> > Francesco Potortì (ricercatore) Voice: +39.050.315.3058

>> > (op.2111)

>> > ISTI - Area della ricerca CNR Mobile: +39.348.8283.107

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http://fly.isti.cnr.it>> > _______________________________________________

>> > Help-octave mailing list

>> >

[hidden email]
>> >

https://mailman.cae.wisc.edu/listinfo/help-octave>>

>> I am not sure I understood.

>> What I get is the following: you want to define vector-valued

>> functions and then be able to operate on those functions (add them,

>> multiply them, etc).

>>

>> I do not think there is built in operator for anonymous handles, that is

>> [1]

>> f = @(x) x.^2

>> g = @(x) x

>> h = f + g

>>

>> and h should be the anonymous function accepting two input argument such

>> that

>> h(x,y) = f(x) + g(y)

>>

>> To emulate this, afaik you have to do it manually (and it wouldn't be

>> efficient)

>> h = @(x,y) f(x) + g(y)

>>

>> Now when you call h, you will be then calling f and g, and since

>> function evaluations are not the most efficient thing, this get worse

>> themore function you nest.

>>

>> @John | Jordi: Can [1], i.e. operators between anonymous functions, be

>> implemented efficiently?

>> --

>> M. Sc. Juan Pablo Carbajal

>> -----

>> PhD Student

>> University of Zürich

>>

http://ailab.ifi.uzh.ch/carbajal/>

>

This is one of many ways to do it.

combined with the elements of g(x). In your example

This is the answer I gave you before. Be aware that this is not

this way.

M. Sc. Juan Pablo Carbajal