On 28 August 2011 12:49, <

[hidden email]> wrote:

> How do I plot this two graphs x=e^0,6667t-1.5 and y_i+1=cos(t^2).

I hope you understand that Octave is not a symbolic calculator, which

you seem to be expecting. To plot in Octave, you actually have to

define all of the points in your plot and then pass all of those

points to the plot command. In particular, you have to specify the

range to plot. The following seems reasonable:

## Define 100 points from -2 to 2

t = linspace(-2, 2, 100);

## Define the points for x(t)

x = exp(0.6667*t) - 1.5;

## Define the point for y_i(t)

y_i = cos(t.^2);

## Plot them together

plot(t,x, t,y)

> I have to find the point of intersection of this two graphs

The easiest way is probably with fsolve:

## Define the two functions

f = @(t) exp(0.6667*t) - 1.5

g = @(t) cos(t.^2)

## Define the function for fsolve

h = @(t) f(t) - g(t)

## Use fsolve to find the zeros of h, with initial guess obtained

## from looking at the plot above

t0 = fsolve(h, 1)

> Sent from my BlackBerry® wireless device

Sent from my Emacs☮ texteditorial device.

HTH,

- Jordi G. H.

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